Simple and Compound_Interest Competitive Exams
100 questions · Mathematics
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Question 1 of 100
Rs. 10,000 is invested for 2 years, earning 10% compound interest in the first year and 20% in the second year. Find the final amount.
ExplanationAmount = P(1+R1/100)(1+R2/100) = 10000(1+10/100)(1+20/100) = Rs. 13,200.
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Question 2 of 100
A sum of Rs. 8,000 is lent at simple interest of 10% per annum for 2 years. Find the total amount to be repaid.
ExplanationSI = (P x R x T)/100 = Rs. 1,600. Amount = Principal + SI = Rs. 8,000 + Rs. 1,600 = Rs. 9,600.
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Question 3 of 100
Rs. 8,000 amounts to simple interest of Rs. 1,440 in 3 years. Find the rate of interest per annum.
ExplanationR = (SI x 100) / (P x T) = (1440 x 100) / (8000 x 3) = 6%.
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Question 4 of 100
The formula for the Amount under Compound Interest (compounded annually) is:
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Question 5 of 100
Find the amount on Rs. 5,000 for 1 year at 8% per annum compound interest, compounded half-yearly.
ExplanationFor half-yearly compounding, Amount = P(1+R/200)^(2T) = 5000(1+8/200)^2 = Rs. 5,408.
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Question 6 of 100
A sum of money doubles itself in 10 years at simple interest. Find the rate of interest per annum.
ExplanationIf a sum doubles at SI in T years, SI equals the principal, so R = 100/T = 100/10 = 10%.
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Question 7 of 100
In how many years will Rs. 6,000 produce Rs. 900 as simple interest at 3% per annum?
ExplanationT = (SI x 100) / (P x R) = (900 x 100) / (6000 x 3) = 5 years.
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Question 8 of 100
At what principal will 9% per annum simple interest amount to Rs. 450 in 2 years?
ExplanationP = (SI x 100) / (R x T) = (450 x 100) / (9 x 2) = Rs. 2,500.
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Question 9 of 100
Rs. 5,000 amounts to simple interest of Rs. 1,000 in 4 years. Find the rate of interest per annum.
ExplanationR = (SI x 100) / (P x T) = (1000 x 100) / (5000 x 4) = 5%.
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Question 10 of 100
For the first year, compound interest and simple interest on the same principal and rate are:
ExplanationIn the first year, compound interest has not yet been compounded on any prior interest, so CI equals SI for that single year.
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Question 11 of 100
If a sum is compounded annually versus half-yearly at the same nominal annual rate for the same time period, which yields a higher final amount?
ExplanationMore frequent compounding periods allow interest to start earning further interest sooner, resulting in a (slightly) higher final amount at the same nominal rate.
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Question 12 of 100
A sum of money doubles itself in 20 years at simple interest. Find the rate of interest per annum.
ExplanationIf a sum doubles at SI in T years, SI equals the principal, so R = 100/T = 100/20 = 5%.
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Question 13 of 100
A sum of money doubles itself in 8 years at simple interest. Find the rate of interest per annum.
ExplanationIf a sum doubles at SI in T years, SI equals the principal, so R = 100/T = 100/8 = 12.50%.
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Question 14 of 100
A sum of money at simple interest amounts to Rs. 720 in 3 years and to Rs. 900 in 5 years. Find the principal sum.
ExplanationAnnual SI = (A2-A1)/(T2-T1) = (900-720)/(5-3) = Rs. 90. Principal = A1 - (SI/year x T1) = Rs. 720 - Rs. 270 = Rs. 450.
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Question 15 of 100
Find the simple interest on Rs. 7,200 at 9% per annum for 3 years.
ExplanationSI = (P x R x T) / 100 = (7200 x 9 x 3) / 100 = Rs. 1,944.
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Question 16 of 100
A sum of money triples itself in 12 years at simple interest. Find the rate of interest per annum.
ExplanationIf the sum becomes 3 times itself, SI = (mult-1) x Principal, so R = (3-1) x 100 / T = 16.67%.
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Question 17 of 100
Find the amount on Rs. 4,000 at 10% per annum compound interest (compounded annually) for 3 years.
ExplanationAmount = P(1+R/100)^T = 4000(1+10/100)^3 = Rs. 5,324.
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Question 18 of 100
Find the simple interest on Rs. 20,000 at 5% per annum for 4 years.
ExplanationSI = (P x R x T) / 100 = (20000 x 5 x 4) / 100 = Rs. 4,000.
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Question 19 of 100
The compound interest on a sum for 2 years at 20% per annum is Rs. 4,200. Find the sum.
ExplanationFor 2 years, CI = P[(1+R/100)^2 - 1]. Solving, P = CI / [(1+R/100)^2 - 1] = Rs. 9,545.45.
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Question 20 of 100
Find the amount on Rs. 8,000 at 5% per annum compound interest (compounded annually) for 3 years.
ExplanationAmount = P(1+R/100)^T = 8000(1+5/100)^3 = Rs. 9,261.
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Question 21 of 100
In how many years will Rs. 5,000 produce Rs. 600 as simple interest at 4% per annum?
ExplanationT = (SI x 100) / (P x R) = (600 x 100) / (5000 x 4) = 3 years.
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Question 22 of 100
Find the difference between the compound interest and simple interest on Rs. 6,000 for 3 years at 10% per annum.
ExplanationFor 3 years, difference (CI - SI) = P x R^2 x (300+R) / 10^6 = Rs. 186.
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Question 23 of 100
Find the difference between the compound interest and simple interest on Rs. 8,000 for 3 years at 5% per annum.
ExplanationFor 3 years, difference (CI - SI) = P x R^2 x (300+R) / 10^6 = Rs. 61.
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Question 24 of 100
Find the simple interest on Rs. 11,000 at 6% per annum for 2 years.
ExplanationSI = (P x R x T) / 100 = (11000 x 6 x 2) / 100 = Rs. 1,320.
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Question 25 of 100
At what principal will 7% per annum simple interest amount to Rs. 2,100 in 4 years?
ExplanationP = (SI x 100) / (R x T) = (2100 x 100) / (7 x 4) = Rs. 7,500.
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Question 26 of 100
Find the simple interest on Rs. 12,000 at 6% per annum for 4 years.
ExplanationSI = (P x R x T) / 100 = (12000 x 6 x 4) / 100 = Rs. 2,880.
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Question 27 of 100
Find the simple interest on Rs. 8,500 at 10% per annum for 2 years.
ExplanationSI = (P x R x T) / 100 = (8500 x 10 x 2) / 100 = Rs. 1,700.
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Question 28 of 100
A sum of money triples itself in 10 years at simple interest. Find the rate of interest per annum.
ExplanationIf the sum becomes 3 times itself, SI = (mult-1) x Principal, so R = (3-1) x 100 / T = 20%.
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Question 29 of 100
At what principal will 4% per annum simple interest amount to Rs. 1,800 in 6 years?
ExplanationP = (SI x 100) / (R x T) = (1800 x 100) / (4 x 6) = Rs. 7,500.
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Question 30 of 100
At what principal will 12% per annum simple interest amount to Rs. 900 in 3 years?
ExplanationP = (SI x 100) / (R x T) = (900 x 100) / (12 x 3) = Rs. 2,500.
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Question 31 of 100
The formula for Simple Interest is generally written as:
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Question 32 of 100
A sum of money becomes 4 times itself in 15 years at simple interest. Find the rate of interest per annum.
ExplanationIf the sum becomes 4 times itself, SI = (mult-1) x Principal, so R = (4-1) x 100 / T = 20%.
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Question 33 of 100
Find the difference between the compound interest and simple interest on Rs. 10,000 for 2 years at 20% per annum.
ExplanationFor 2 years, difference (CI - SI) = P x (R/100)^2 = 10000 x (20/100)^2 = Rs. 400.
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Question 34 of 100
Find the amount on Rs. 20,000 for 1 year at 10% per annum compound interest, compounded half-yearly.
ExplanationFor half-yearly compounding, Amount = P(1+R/200)^(2T) = 20000(1+10/200)^2 = Rs. 22,050.
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Question 35 of 100
In how many years will Rs. 4,000 produce Rs. 720 as simple interest at 6% per annum?
ExplanationT = (SI x 100) / (P x R) = (720 x 100) / (4000 x 6) = 3 years.
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Question 36 of 100
Find the compound interest on Rs. 8,000 at 5% per annum for 2 years, compounded annually.
ExplanationAmount = P(1+R/100)^T = 8000(1+5/100)^2 = Rs. 8,820. CI = Amount - Principal = Rs. 8,820 - Rs. 8,000 = Rs. 820.
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Question 37 of 100
A sum of money at simple interest amounts to Rs. 600 in 2 years and to Rs. 780 in 5 years. Find the principal sum.
ExplanationAnnual SI = (A2-A1)/(T2-T1) = (780-600)/(5-2) = Rs. 60. Principal = A1 - (SI/year x T1) = Rs. 600 - Rs. 120 = Rs. 480.
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Question 38 of 100
Find the simple interest on Rs. 15,000 at 4% per annum for 3 years.
ExplanationSI = (P x R x T) / 100 = (15000 x 4 x 3) / 100 = Rs. 1,800.
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Question 39 of 100
Find the simple interest on Rs. 9,600 at 8% per annum for 4 years.
ExplanationSI = (P x R x T) / 100 = (9600 x 8 x 4) / 100 = Rs. 3,072.
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Question 40 of 100
A sum of Rs. 5,000 is lent at simple interest of 6% per annum for 3 years. Find the total amount to be repaid.
ExplanationSI = (P x R x T)/100 = Rs. 900. Amount = Principal + SI = Rs. 5,000 + Rs. 900 = Rs. 5,900.
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Question 41 of 100
A sum of Rs. 20,000 is lent at simple interest of 4% per annum for 3 years. Find the total amount to be repaid.
ExplanationSI = (P x R x T)/100 = Rs. 2,400. Amount = Principal + SI = Rs. 20,000 + Rs. 2,400 = Rs. 22,400.
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Question 42 of 100
Find the amount on Rs. 8,000 for 1 year at 20% per annum compound interest, compounded half-yearly.
ExplanationFor half-yearly compounding, Amount = P(1+R/200)^(2T) = 8000(1+20/200)^2 = Rs. 9,680.
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Question 43 of 100
At what principal will 8% per annum simple interest amount to Rs. 960 in 3 years?
ExplanationP = (SI x 100) / (R x T) = (960 x 100) / (8 x 3) = Rs. 4,000.
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Question 44 of 100
Find the compound interest on Rs. 4,000 at 25% per annum for 2 years, compounded annually.
ExplanationAmount = P(1+R/100)^T = 4000(1+25/100)^2 = Rs. 6,250. CI = Amount - Principal = Rs. 6,250 - Rs. 4,000 = Rs. 2,250.
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Question 45 of 100
In how many years will Rs. 10,000 produce Rs. 2,000 as simple interest at 4% per annum?
ExplanationT = (SI x 100) / (P x R) = (2000 x 100) / (10000 x 4) = 5 years.
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Question 46 of 100
Find the compound interest on Rs. 5,000 at 10% per annum for 2 years, compounded annually.
ExplanationAmount = P(1+R/100)^T = 5000(1+10/100)^2 = Rs. 6,050. CI = Amount - Principal = Rs. 6,050 - Rs. 5,000 = Rs. 1,050.
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Question 47 of 100
Find the difference between the compound interest and simple interest on Rs. 5,000 for 2 years at 10% per annum.
ExplanationFor 2 years, difference (CI - SI) = P x (R/100)^2 = 5000 x (10/100)^2 = Rs. 50.
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Question 48 of 100
A sum of money doubles itself in 4 years at simple interest. Find the rate of interest per annum.
ExplanationIf a sum doubles at SI in T years, SI equals the principal, so R = 100/T = 100/4 = 25%.
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Question 49 of 100
Find the difference between the compound interest and simple interest on Rs. 10,000 for 3 years at 10% per annum.
ExplanationFor 3 years, difference (CI - SI) = P x R^2 x (300+R) / 10^6 = Rs. 310.
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Question 50 of 100
The compound interest on a sum for 2 years at 25% per annum is Rs. 1,250. Find the sum.
ExplanationFor 2 years, CI = P[(1+R/100)^2 - 1]. Solving, P = CI / [(1+R/100)^2 - 1] = Rs. 2,222.22.
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Question 51 of 100
A sum of Rs. 15,000 is lent at simple interest of 5% per annum for 4 years. Find the total amount to be repaid.
ExplanationSI = (P x R x T)/100 = Rs. 3,000. Amount = Principal + SI = Rs. 15,000 + Rs. 3,000 = Rs. 18,000.
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Question 52 of 100
Find the compound interest on Rs. 10,000 at 20% per annum for 2 years, compounded annually.
ExplanationAmount = P(1+R/100)^T = 10000(1+20/100)^2 = Rs. 14,400. CI = Amount - Principal = Rs. 14,400 - Rs. 10,000 = Rs. 4,400.
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Question 53 of 100
In how many years will Rs. 7,500 produce Rs. 1,125 as simple interest at 3% per annum?
ExplanationT = (SI x 100) / (P x R) = (1125 x 100) / (7500 x 3) = 5 years.
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Question 54 of 100
At what principal will 10% per annum simple interest amount to Rs. 750 in 3 years?
ExplanationP = (SI x 100) / (R x T) = (750 x 100) / (10 x 3) = Rs. 2,500.
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Question 55 of 100
In how many years will Rs. 8,000 produce Rs. 1,600 as simple interest at 5% per annum?
ExplanationT = (SI x 100) / (P x R) = (1600 x 100) / (8000 x 5) = 4 years.
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Question 56 of 100
Rs. 7,500 amounts to simple interest of Rs. 1,500 in 4 years. Find the rate of interest per annum.
ExplanationR = (SI x 100) / (P x T) = (1500 x 100) / (7500 x 4) = 5%.
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Question 57 of 100
Rs. 10,000 amounts to simple interest of Rs. 2,000 in 4 years. Find the rate of interest per annum.
ExplanationR = (SI x 100) / (P x T) = (2000 x 100) / (10000 x 4) = 5%.
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Question 58 of 100
Find the simple interest on Rs. 4,000 at 5% per annum for 3 years.
ExplanationSI = (P x R x T) / 100 = (4000 x 5 x 3) / 100 = Rs. 600.
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Question 59 of 100
Find the simple interest on Rs. 6,500 at 8% per annum for 2 years.
ExplanationSI = (P x R x T) / 100 = (6500 x 8 x 2) / 100 = Rs. 1,040.
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Question 60 of 100
Find the simple interest on Rs. 18,000 at 3% per annum for 5 years.
ExplanationSI = (P x R x T) / 100 = (18000 x 3 x 5) / 100 = Rs. 2,700.
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Question 61 of 100
A sum of money doubles itself in 16 years at simple interest. Find the rate of interest per annum.
ExplanationIf a sum doubles at SI in T years, SI equals the principal, so R = 100/T = 100/16 = 6.25%.
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Question 62 of 100
Rs. 20,000 is invested for 2 years, earning 10% compound interest in the first year and 5% in the second year. Find the final amount.
ExplanationAmount = P(1+R1/100)(1+R2/100) = 20000(1+10/100)(1+5/100) = Rs. 23,100.
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Question 63 of 100
Find the simple interest on Rs. 9,000 at 7% per annum for 5 years.
ExplanationSI = (P x R x T) / 100 = (9000 x 7 x 5) / 100 = Rs. 3,150.
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Question 64 of 100
A sum of Rs. 6,400 is lent at simple interest of 9% per annum for 3 years. Find the total amount to be repaid.
ExplanationSI = (P x R x T)/100 = Rs. 1,728. Amount = Principal + SI = Rs. 6,400 + Rs. 1,728 = Rs. 8,128.
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Question 65 of 100
A sum of Rs. 10,000 is lent at simple interest of 8% per annum for 5 years. Find the total amount to be repaid.
ExplanationSI = (P x R x T)/100 = Rs. 4,000. Amount = Principal + SI = Rs. 10,000 + Rs. 4,000 = Rs. 14,000.
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Question 66 of 100
A sum of money at simple interest amounts to Rs. 500 in 3 years and to Rs. 650 in 7 years. Find the principal sum.
ExplanationAnnual SI = (A2-A1)/(T2-T1) = (650-500)/(7-3) = Rs. 37.50. Principal = A1 - (SI/year x T1) = Rs. 500 - Rs. 112.50 = Rs. 387.50.
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Question 67 of 100
Rs. 6,000 amounts to simple interest of Rs. 900 in 5 years. Find the rate of interest per annum.
ExplanationR = (SI x 100) / (P x T) = (900 x 100) / (6000 x 5) = 3%.
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Question 68 of 100
The compound interest on a sum for 2 years at 10% per annum is Rs. 1,050. Find the sum.
ExplanationFor 2 years, CI = P[(1+R/100)^2 - 1]. Solving, P = CI / [(1+R/100)^2 - 1] = Rs. 5,000.
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Question 69 of 100
Find the difference between the compound interest and simple interest on Rs. 6,000 for 2 years at 10% per annum.
ExplanationFor 2 years, difference (CI - SI) = P x (R/100)^2 = 6000 x (10/100)^2 = Rs. 60.
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Question 70 of 100
Rs. 8,000 is invested for 2 years, earning 5% compound interest in the first year and 10% in the second year. Find the final amount.
ExplanationAmount = P(1+R1/100)(1+R2/100) = 8000(1+5/100)(1+10/100) = Rs. 9,240.
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Question 71 of 100
Find the compound interest on Rs. 20,000 at 10% per annum for 2 years, compounded annually.
ExplanationAmount = P(1+R/100)^T = 20000(1+10/100)^2 = Rs. 24,200. CI = Amount - Principal = Rs. 24,200 - Rs. 20,000 = Rs. 4,200.
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Question 72 of 100
A sum of money triples itself in 8 years at simple interest. Find the rate of interest per annum.
ExplanationIf the sum becomes 3 times itself, SI = (mult-1) x Principal, so R = (3-1) x 100 / T = 25%.
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Question 73 of 100
Find the amount on Rs. 5,000 at 10% per annum compound interest (compounded annually) for 3 years.
ExplanationAmount = P(1+R/100)^T = 5000(1+10/100)^3 = Rs. 6,655.
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Question 74 of 100
Rs. 5,000 is invested for 2 years, earning 20% compound interest in the first year and 10% in the second year. Find the final amount.
ExplanationAmount = P(1+R1/100)(1+R2/100) = 5000(1+20/100)(1+10/100) = Rs. 6,600.
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Question 75 of 100
A sum of money at simple interest amounts to Rs. 800 in 2 years and to Rs. 1,040 in 6 years. Find the principal sum.
ExplanationAnnual SI = (A2-A1)/(T2-T1) = (1040-800)/(6-2) = Rs. 60. Principal = A1 - (SI/year x T1) = Rs. 800 - Rs. 120 = Rs. 680.
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Question 76 of 100
Find the difference between the compound interest and simple interest on Rs. 5,000 for 3 years at 10% per annum.
ExplanationFor 3 years, difference (CI - SI) = P x R^2 x (300+R) / 10^6 = Rs. 155.
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Question 77 of 100
Find the difference between the compound interest and simple interest on Rs. 12,000 for 2 years at 8% per annum.
ExplanationFor 2 years, difference (CI - SI) = P x (R/100)^2 = 12000 x (8/100)^2 = Rs. 76.80.
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Question 78 of 100
At what principal will 6% per annum simple interest amount to Rs. 1,200 in 5 years?
ExplanationP = (SI x 100) / (R x T) = (1200 x 100) / (6 x 5) = Rs. 4,000.
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Question 79 of 100
Find the difference between the compound interest and simple interest on Rs. 4,000 for 3 years at 10% per annum.
ExplanationFor 3 years, difference (CI - SI) = P x R^2 x (300+R) / 10^6 = Rs. 124.
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Question 80 of 100
Rs. 4,000 amounts to simple interest of Rs. 600 in 3 years. Find the rate of interest per annum.
ExplanationR = (SI x 100) / (P x T) = (600 x 100) / (4000 x 3) = 5%.
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Question 81 of 100
A sum of money doubles itself in 25 years at simple interest. Find the rate of interest per annum.
ExplanationIf a sum doubles at SI in T years, SI equals the principal, so R = 100/T = 100/25 = 4%.
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Question 82 of 100
Find the amount on Rs. 6,000 at 20% per annum compound interest (compounded annually) for 3 years.
ExplanationAmount = P(1+R/100)^T = 6000(1+20/100)^3 = Rs. 10,368.
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Question 83 of 100
Find the amount on Rs. 10,000 for 1 year at 10% per annum compound interest, compounded half-yearly.
ExplanationFor half-yearly compounding, Amount = P(1+R/200)^(2T) = 10000(1+10/200)^2 = Rs. 11,025.
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Question 84 of 100
A sum of money becomes 4 times itself in 20 years at simple interest. Find the rate of interest per annum.
ExplanationIf the sum becomes 4 times itself, SI = (mult-1) x Principal, so R = (4-1) x 100 / T = 15%.
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Question 85 of 100
Find the compound interest on Rs. 6,400 at 25% per annum for 2 years, compounded annually.
ExplanationAmount = P(1+R/100)^T = 6400(1+25/100)^2 = Rs. 10,000. CI = Amount - Principal = Rs. 10,000 - Rs. 6,400 = Rs. 3,600.
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Question 86 of 100
Find the compound interest on Rs. 12,500 at 8% per annum for 2 years, compounded annually.
ExplanationAmount = P(1+R/100)^T = 12500(1+8/100)^2 = Rs. 14,580. CI = Amount - Principal = Rs. 14,580 - Rs. 12,500 = Rs. 2,080.
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Question 87 of 100
Rs. 3,000 amounts to simple interest of Rs. 450 in 3 years. Find the rate of interest per annum.
ExplanationR = (SI x 100) / (P x T) = (450 x 100) / (3000 x 3) = 5%.
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Question 88 of 100
The compound interest on a sum for 2 years at 5% per annum is Rs. 820. Find the sum.
ExplanationFor 2 years, CI = P[(1+R/100)^2 - 1]. Solving, P = CI / [(1+R/100)^2 - 1] = Rs. 8,000.
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Question 89 of 100
At what principal will 5% per annum simple interest amount to Rs. 600 in 4 years?
ExplanationP = (SI x 100) / (R x T) = (600 x 100) / (5 x 4) = Rs. 3,000.
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Question 90 of 100
Find the amount on Rs. 4,000 for 1.5 years at 10% per annum compound interest, compounded half-yearly.
ExplanationFor half-yearly compounding, Amount = P(1+R/200)^(2T) = 4000(1+10/200)^3.0 = Rs. 4,630.50.
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Question 91 of 100
Find the simple interest on Rs. 5,600 at 12% per annum for 3 years.
ExplanationSI = (P x R x T) / 100 = (5600 x 12 x 3) / 100 = Rs. 2,016.
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Question 92 of 100
Find the amount on Rs. 10,000 at 10% per annum compound interest (compounded annually) for 3 years.
ExplanationAmount = P(1+R/100)^T = 10000(1+10/100)^3 = Rs. 13,310.
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Question 93 of 100
A sum of Rs. 7,500 is lent at simple interest of 12% per annum for 2 years. Find the total amount to be repaid.
ExplanationSI = (P x R x T)/100 = Rs. 1,800. Amount = Principal + SI = Rs. 7,500 + Rs. 1,800 = Rs. 9,300.
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Question 94 of 100
Compared to simple interest at the same rate and principal, compound interest over more than one year is:
ExplanationBecause compound interest earns 'interest on interest', it always exceeds simple interest for periods beyond one year (at a positive rate).
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Question 95 of 100
Rs. 4,000 is invested for 2 years, earning 25% compound interest in the first year and 20% in the second year. Find the final amount.
ExplanationAmount = P(1+R1/100)(1+R2/100) = 4000(1+25/100)(1+20/100) = Rs. 6,000.
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Question 96 of 100
A sum of money doubles itself in 5 years at simple interest. Find the rate of interest per annum.
ExplanationIf a sum doubles at SI in T years, SI equals the principal, so R = 100/T = 100/5 = 20%.
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Question 97 of 100
The compound interest on a sum for 2 years at 10% per annum is Rs. 630. Find the sum.
ExplanationFor 2 years, CI = P[(1+R/100)^2 - 1]. Solving, P = CI / [(1+R/100)^2 - 1] = Rs. 3,000.
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Question 98 of 100
Find the difference between the compound interest and simple interest on Rs. 4,000 for 2 years at 25% per annum.
ExplanationFor 2 years, difference (CI - SI) = P x (R/100)^2 = 4000 x (25/100)^2 = Rs. 250.
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Question 99 of 100
Find the difference between the compound interest and simple interest on Rs. 8,000 for 2 years at 5% per annum.
ExplanationFor 2 years, difference (CI - SI) = P x (R/100)^2 = 8000 x (5/100)^2 = Rs. 20.
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Question 100 of 100
A sum of Rs. 12,500 is lent at simple interest of 6% per annum for 4 years. Find the total amount to be repaid.
ExplanationSI = (P x R x T)/100 = Rs. 3,000. Amount = Principal + SI = Rs. 12,500 + Rs. 3,000 = Rs. 15,500.
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