Time Work Pipes Competitive Exams
100 questions · Mathematics
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Question 1 of 100
A can do a piece of work in 10 days and B can do the same work in 12 days. Working together, in how many days will they finish the work?
ExplanationTotal work = LCM(10, 12) = 60 units. A's efficiency = 6 units/day, B's = 5. Combined efficiency = 11. Time = 60/11 = 5.45 days. Tip: LCM method avoids complex fraction additions.
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Question 2 of 100
A is 4 times as efficient as B. If B takes 22 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 22/4 = 5.5. Efficiencies: A=4, B=1. Total work = 22×1 = 22. Time together = Work / Total Eff = 22 / (4+1) = 4.4 days. Tip: Efficiency is inversely proportional to Time.
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Question 3 of 100
A is 3 times as efficient as B. If B takes 36 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 36/3 = 12.0. Efficiencies: A=3, B=1. Total work = 36×1 = 36. Time together = Work / Total Eff = 36 / (3+1) = 9.0 days. Tip: Efficiency is inversely proportional to Time.
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Question 4 of 100
A is 2 times as efficient as B. If B takes 25 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 25/2 = 12.5. Efficiencies: A=2, B=1. Total work = 25×1 = 25. Time together = Work / Total Eff = 25 / (2+1) = 8.33 days. Tip: Efficiency is inversely proportional to Time.
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Question 5 of 100
A can do a piece of work in 15 days and B can do the same work in 20 days. Working together, in how many days will they finish the work?
ExplanationTotal work = LCM(15, 20) = 60 units. A's efficiency = 4 units/day, B's = 3. Combined efficiency = 7. Time = 60/7 = 8.57 days. Tip: LCM method avoids complex fraction additions.
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Question 6 of 100
A is 4 times as efficient as B. If B takes 39 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 39/4 = 9.75. Efficiencies: A=4, B=1. Total work = 39×1 = 39. Time together = Work / Total Eff = 39 / (4+1) = 7.8 days. Tip: Efficiency is inversely proportional to Time.
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Question 7 of 100
A can do a piece of work in 30 days and B can do the same work in 15 days. Working together, in how many days will they finish the work?
ExplanationTotal work = LCM(30, 15) = 30 units. A's efficiency = 1 units/day, B's = 2. Combined efficiency = 3. Time = 30/3 = 10.0 days. Tip: LCM method avoids complex fraction additions.
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Question 8 of 100
A is 3 times as efficient as B. If B takes 32 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 32/3 = 10.67. Efficiencies: A=3, B=1. Total work = 32×1 = 32. Time together = Work / Total Eff = 32 / (3+1) = 8.0 days. Tip: Efficiency is inversely proportional to Time.
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Question 9 of 100
A is 3 times as efficient as B. If B takes 22 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 22/3 = 7.33. Efficiencies: A=3, B=1. Total work = 22×1 = 22. Time together = Work / Total Eff = 22 / (3+1) = 5.5 days. Tip: Efficiency is inversely proportional to Time.
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Question 10 of 100
Pipe A can fill a tank in 15 hours and Pipe B can fill it in 30 hours. How long will it take to fill the tank if both are opened together?
ExplanationLCM of 15, 30 is 30 (Total capacity). Eff A = 2, Eff B = 1. Time = 30 / (2 + 1) = 10.0 hours. Tip: Same logic as Time & Work.
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Question 11 of 100
Pipe A can fill a tank in 10 hours and Pipe B can fill it in 12 hours. How long will it take to fill the tank if both are opened together?
ExplanationLCM of 10, 12 is 60 (Total capacity). Eff A = 6, Eff B = 5. Time = 60 / (6 + 5) = 5.45 hours. Tip: Same logic as Time & Work.
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Question 12 of 100
A can do a work in 15 days, B in 30 days. A works for 3 days and leaves. In how many days can B finish the remaining work?
ExplanationTotal Work = LCM = 30. A's eff=2, B's eff=1. A's work in 3 days = 6. Remaining = 24. B takes 24/1 = 24.0 days. Tip: Calculate remaining work before changing dividing efficiency.
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Question 13 of 100
A is 3 times as efficient as B. If B takes 33 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 33/3 = 11.0. Efficiencies: A=3, B=1. Total work = 33×1 = 33. Time together = Work / Total Eff = 33 / (3+1) = 8.25 days. Tip: Efficiency is inversely proportional to Time.
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Question 14 of 100
A is 2 times as efficient as B. If B takes 30 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 30/2 = 15.0. Efficiencies: A=2, B=1. Total work = 30×1 = 30. Time together = Work / Total Eff = 30 / (2+1) = 10.0 days. Tip: Efficiency is inversely proportional to Time.
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Question 15 of 100
A is 2 times as efficient as B. If B takes 20 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 20/2 = 10.0. Efficiencies: A=2, B=1. Total work = 20×1 = 20. Time together = Work / Total Eff = 20 / (2+1) = 6.67 days. Tip: Efficiency is inversely proportional to Time.
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Question 16 of 100
Pipe A can fill a tank in 10 hours and Pipe B can fill it in 20 hours. How long will it take to fill the tank if both are opened together?
ExplanationLCM of 10, 20 is 20 (Total capacity). Eff A = 2, Eff B = 1. Time = 20 / (2 + 1) = 6.67 hours. Tip: Same logic as Time & Work.
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Question 17 of 100
A can do a work in 20 days, B in 30 days. A works for 3 days and leaves. In how many days can B finish the remaining work?
ExplanationTotal Work = LCM = 60. A's eff=3, B's eff=2. A's work in 3 days = 9. Remaining = 51. B takes 51/2 = 25.5 days. Tip: Calculate remaining work before changing dividing efficiency.
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Question 18 of 100
A is 4 times as efficient as B. If B takes 40 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 40/4 = 10.0. Efficiencies: A=4, B=1. Total work = 40×1 = 40. Time together = Work / Total Eff = 40 / (4+1) = 8.0 days. Tip: Efficiency is inversely proportional to Time.
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Question 19 of 100
A can do a piece of work in 10 days and B can do the same work in 10 days. Working together, in how many days will they finish the work?
ExplanationTotal work = LCM(10, 10) = 10 units. A's efficiency = 1 units/day, B's = 1. Combined efficiency = 2. Time = 10/2 = 5.0 days. Tip: LCM method avoids complex fraction additions.
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Question 20 of 100
A can do a work in 20 days, B in 30 days. A works for 5 days and leaves. In how many days can B finish the remaining work?
ExplanationTotal Work = LCM = 60. A's eff=3, B's eff=2. A's work in 5 days = 15. Remaining = 45. B takes 45/2 = 22.5 days. Tip: Calculate remaining work before changing dividing efficiency.
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Question 21 of 100
Pipe A can fill a tank in 5 hours while Pipe B can empty the full tank in 15 hours. If both are opened together, in how many hours will the tank be filled?
ExplanationCapacity = LCM(5,15) = 15. Net efficiency = Fill(3) - Empty(1) = 2. Time = 15 / 2 = 7.5 hours. Tip: Treat emptying pipes as negative efficiency.
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Question 22 of 100
A can do a work in 15 days, B in 30 days. A works for 4 days and leaves. In how many days can B finish the remaining work?
ExplanationTotal Work = LCM = 30. A's eff=2, B's eff=1. A's work in 4 days = 8. Remaining = 22. B takes 22/1 = 22.0 days. Tip: Calculate remaining work before changing dividing efficiency.
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Question 23 of 100
A can do a piece of work in 20 days and B can do the same work in 10 days. Working together, in how many days will they finish the work?
ExplanationTotal work = LCM(20, 10) = 20 units. A's efficiency = 1 units/day, B's = 2. Combined efficiency = 3. Time = 20/3 = 6.67 days. Tip: LCM method avoids complex fraction additions.
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Question 24 of 100
A can do a work in 25 days, B in 30 days. A works for 4 days and leaves. In how many days can B finish the remaining work?
ExplanationTotal Work = LCM = 150. A's eff=6, B's eff=5. A's work in 4 days = 24. Remaining = 126. B takes 126/5 = 25.2 days. Tip: Calculate remaining work before changing dividing efficiency.
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Question 25 of 100
A can do a piece of work in 30 days and B can do the same work in 12 days. Working together, in how many days will they finish the work?
ExplanationTotal work = LCM(30, 12) = 60 units. A's efficiency = 2 units/day, B's = 5. Combined efficiency = 7. Time = 60/7 = 8.57 days. Tip: LCM method avoids complex fraction additions.
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Question 26 of 100
Pipe A can fill a tank in 20 hours and Pipe B can fill it in 30 hours. How long will it take to fill the tank if both are opened together?
ExplanationLCM of 20, 30 is 60 (Total capacity). Eff A = 3, Eff B = 2. Time = 60 / (3 + 2) = 12.0 hours. Tip: Same logic as Time & Work.
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Question 27 of 100
A is 3 times as efficient as B. If B takes 39 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 39/3 = 13.0. Efficiencies: A=3, B=1. Total work = 39×1 = 39. Time together = Work / Total Eff = 39 / (3+1) = 9.75 days. Tip: Efficiency is inversely proportional to Time.
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Question 28 of 100
A is 4 times as efficient as B. If B takes 38 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 38/4 = 9.5. Efficiencies: A=4, B=1. Total work = 38×1 = 38. Time together = Work / Total Eff = 38 / (4+1) = 7.6 days. Tip: Efficiency is inversely proportional to Time.
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Question 29 of 100
A can do a piece of work in 15 days and B can do the same work in 10 days. Working together, in how many days will they finish the work?
ExplanationTotal work = LCM(15, 10) = 30 units. A's efficiency = 2 units/day, B's = 3. Combined efficiency = 5. Time = 30/5 = 6.0 days. Tip: LCM method avoids complex fraction additions.
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Question 30 of 100
A is 2 times as efficient as B. If B takes 36 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 36/2 = 18.0. Efficiencies: A=2, B=1. Total work = 36×1 = 36. Time together = Work / Total Eff = 36 / (2+1) = 12.0 days. Tip: Efficiency is inversely proportional to Time.
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Question 31 of 100
A is 3 times as efficient as B. If B takes 23 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 23/3 = 7.67. Efficiencies: A=3, B=1. Total work = 23×1 = 23. Time together = Work / Total Eff = 23 / (3+1) = 5.75 days. Tip: Efficiency is inversely proportional to Time.
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Question 32 of 100
A can do a piece of work in 12 days and B can do the same work in 30 days. Working together, in how many days will they finish the work?
ExplanationTotal work = LCM(12, 30) = 60 units. A's efficiency = 5 units/day, B's = 2. Combined efficiency = 7. Time = 60/7 = 8.57 days. Tip: LCM method avoids complex fraction additions.
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Question 33 of 100
A can do a work in 20 days, B in 20 days. A works for 3 days and leaves. In how many days can B finish the remaining work?
ExplanationTotal Work = LCM = 20. A's eff=1, B's eff=1. A's work in 3 days = 3. Remaining = 17. B takes 17/1 = 17.0 days. Tip: Calculate remaining work before changing dividing efficiency.
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Question 34 of 100
A is 3 times as efficient as B. If B takes 20 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 20/3 = 6.67. Efficiencies: A=3, B=1. Total work = 20×1 = 20. Time together = Work / Total Eff = 20 / (3+1) = 5.0 days. Tip: Efficiency is inversely proportional to Time.
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Question 35 of 100
A can do a piece of work in 10 days and B can do the same work in 15 days. Working together, in how many days will they finish the work?
ExplanationTotal work = LCM(10, 15) = 30 units. A's efficiency = 3 units/day, B's = 2. Combined efficiency = 5. Time = 30/5 = 6.0 days. Tip: LCM method avoids complex fraction additions.
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Question 36 of 100
A can do a work in 20 days, B in 20 days. A works for 2 days and leaves. In how many days can B finish the remaining work?
ExplanationTotal Work = LCM = 20. A's eff=1, B's eff=1. A's work in 2 days = 2. Remaining = 18. B takes 18/1 = 18.0 days. Tip: Calculate remaining work before changing dividing efficiency.
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Question 37 of 100
A is 2 times as efficient as B. If B takes 34 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 34/2 = 17.0. Efficiencies: A=2, B=1. Total work = 34×1 = 34. Time together = Work / Total Eff = 34 / (2+1) = 11.33 days. Tip: Efficiency is inversely proportional to Time.
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Question 38 of 100
Pipe A can fill a tank in 15 hours and Pipe B can fill it in 20 hours. How long will it take to fill the tank if both are opened together?
ExplanationLCM of 15, 20 is 60 (Total capacity). Eff A = 4, Eff B = 3. Time = 60 / (4 + 3) = 8.57 hours. Tip: Same logic as Time & Work.
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Question 39 of 100
A can do a piece of work in 10 days and B can do the same work in 20 days. Working together, in how many days will they finish the work?
ExplanationTotal work = LCM(10, 20) = 20 units. A's efficiency = 2 units/day, B's = 1. Combined efficiency = 3. Time = 20/3 = 6.67 days. Tip: LCM method avoids complex fraction additions.
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Question 40 of 100
A is 2 times as efficient as B. If B takes 24 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 24/2 = 12.0. Efficiencies: A=2, B=1. Total work = 24×1 = 24. Time together = Work / Total Eff = 24 / (2+1) = 8.0 days. Tip: Efficiency is inversely proportional to Time.
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Question 41 of 100
A can do a piece of work in 20 days and B can do the same work in 15 days. Working together, in how many days will they finish the work?
ExplanationTotal work = LCM(20, 15) = 60 units. A's efficiency = 3 units/day, B's = 4. Combined efficiency = 7. Time = 60/7 = 8.57 days. Tip: LCM method avoids complex fraction additions.
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Question 42 of 100
A is 2 times as efficient as B. If B takes 38 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 38/2 = 19.0. Efficiencies: A=2, B=1. Total work = 38×1 = 38. Time together = Work / Total Eff = 38 / (2+1) = 12.67 days. Tip: Efficiency is inversely proportional to Time.
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Question 43 of 100
A can do a piece of work in 30 days and B can do the same work in 30 days. Working together, in how many days will they finish the work?
ExplanationTotal work = LCM(30, 30) = 30 units. A's efficiency = 1 units/day, B's = 1. Combined efficiency = 2. Time = 30/2 = 15.0 days. Tip: LCM method avoids complex fraction additions.
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Question 44 of 100
A can do a work in 20 days, B in 20 days. A works for 4 days and leaves. In how many days can B finish the remaining work?
ExplanationTotal Work = LCM = 20. A's eff=1, B's eff=1. A's work in 4 days = 4. Remaining = 16. B takes 16/1 = 16.0 days. Tip: Calculate remaining work before changing dividing efficiency.
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Question 45 of 100
Pipe A can fill a tank in 15 hours while Pipe B can empty the full tank in 25 hours. If both are opened together, in how many hours will the tank be filled?
ExplanationCapacity = LCM(15,25) = 75. Net efficiency = Fill(5) - Empty(3) = 2. Time = 75 / 2 = 37.5 hours. Tip: Treat emptying pipes as negative efficiency.
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Question 46 of 100
A can do a piece of work in 15 days and B can do the same work in 30 days. Working together, in how many days will they finish the work?
ExplanationTotal work = LCM(15, 30) = 30 units. A's efficiency = 2 units/day, B's = 1. Combined efficiency = 3. Time = 30/3 = 10.0 days. Tip: LCM method avoids complex fraction additions.
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Question 47 of 100
A is 4 times as efficient as B. If B takes 34 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 34/4 = 8.5. Efficiencies: A=4, B=1. Total work = 34×1 = 34. Time together = Work / Total Eff = 34 / (4+1) = 6.8 days. Tip: Efficiency is inversely proportional to Time.
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Question 48 of 100
A can do a work in 15 days, B in 20 days. A works for 4 days and leaves. In how many days can B finish the remaining work?
ExplanationTotal Work = LCM = 60. A's eff=4, B's eff=3. A's work in 4 days = 16. Remaining = 44. B takes 44/3 = 14.67 days. Tip: Calculate remaining work before changing dividing efficiency.
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Question 49 of 100
A can do a piece of work in 15 days and B can do the same work in 12 days. Working together, in how many days will they finish the work?
ExplanationTotal work = LCM(15, 12) = 60 units. A's efficiency = 4 units/day, B's = 5. Combined efficiency = 9. Time = 60/9 = 6.67 days. Tip: LCM method avoids complex fraction additions.
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Question 50 of 100
A can do a work in 25 days, B in 20 days. A works for 4 days and leaves. In how many days can B finish the remaining work?
ExplanationTotal Work = LCM = 100. A's eff=4, B's eff=5. A's work in 4 days = 16. Remaining = 84. B takes 84/5 = 16.8 days. Tip: Calculate remaining work before changing dividing efficiency.
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Question 51 of 100
A can do a piece of work in 10 days and B can do the same work in 30 days. Working together, in how many days will they finish the work?
ExplanationTotal work = LCM(10, 30) = 30 units. A's efficiency = 3 units/day, B's = 1. Combined efficiency = 4. Time = 30/4 = 7.5 days. Tip: LCM method avoids complex fraction additions.
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Question 52 of 100
Pipe A can fill a tank in 10 hours while Pipe B can empty the full tank in 20 hours. If both are opened together, in how many hours will the tank be filled?
ExplanationCapacity = LCM(10,20) = 20. Net efficiency = Fill(2) - Empty(1) = 1. Time = 20 / 1 = 20.0 hours. Tip: Treat emptying pipes as negative efficiency.
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Question 53 of 100
A can do a work in 25 days, B in 30 days. A works for 2 days and leaves. In how many days can B finish the remaining work?
ExplanationTotal Work = LCM = 150. A's eff=6, B's eff=5. A's work in 2 days = 12. Remaining = 138. B takes 138/5 = 27.6 days. Tip: Calculate remaining work before changing dividing efficiency.
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Question 54 of 100
A can do a work in 15 days, B in 20 days. A works for 3 days and leaves. In how many days can B finish the remaining work?
ExplanationTotal Work = LCM = 60. A's eff=4, B's eff=3. A's work in 3 days = 12. Remaining = 48. B takes 48/3 = 16.0 days. Tip: Calculate remaining work before changing dividing efficiency.
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Question 55 of 100
A is 2 times as efficient as B. If B takes 35 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 35/2 = 17.5. Efficiencies: A=2, B=1. Total work = 35×1 = 35. Time together = Work / Total Eff = 35 / (2+1) = 11.67 days. Tip: Efficiency is inversely proportional to Time.
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Question 56 of 100
A is 4 times as efficient as B. If B takes 30 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 30/4 = 7.5. Efficiencies: A=4, B=1. Total work = 30×1 = 30. Time together = Work / Total Eff = 30 / (4+1) = 6.0 days. Tip: Efficiency is inversely proportional to Time.
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Question 57 of 100
Pipe A can fill a tank in 10 hours and Pipe B can fill it in 30 hours. How long will it take to fill the tank if both are opened together?
ExplanationLCM of 10, 30 is 30 (Total capacity). Eff A = 3, Eff B = 1. Time = 30 / (3 + 1) = 7.5 hours. Tip: Same logic as Time & Work.
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Question 58 of 100
Pipe A can fill a tank in 15 hours and Pipe B can fill it in 12 hours. How long will it take to fill the tank if both are opened together?
ExplanationLCM of 15, 12 is 60 (Total capacity). Eff A = 4, Eff B = 5. Time = 60 / (4 + 5) = 6.67 hours. Tip: Same logic as Time & Work.
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Question 59 of 100
A is 3 times as efficient as B. If B takes 25 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 25/3 = 8.33. Efficiencies: A=3, B=1. Total work = 25×1 = 25. Time together = Work / Total Eff = 25 / (3+1) = 6.25 days. Tip: Efficiency is inversely proportional to Time.
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Question 60 of 100
A can do a piece of work in 15 days and B can do the same work in 15 days. Working together, in how many days will they finish the work?
ExplanationTotal work = LCM(15, 15) = 15 units. A's efficiency = 1 units/day, B's = 1. Combined efficiency = 2. Time = 15/2 = 7.5 days. Tip: LCM method avoids complex fraction additions.
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Question 61 of 100
A can do a piece of work in 12 days and B can do the same work in 12 days. Working together, in how many days will they finish the work?
ExplanationTotal work = LCM(12, 12) = 12 units. A's efficiency = 1 units/day, B's = 1. Combined efficiency = 2. Time = 12/2 = 6.0 days. Tip: LCM method avoids complex fraction additions.
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Question 62 of 100
A is 3 times as efficient as B. If B takes 35 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 35/3 = 11.67. Efficiencies: A=3, B=1. Total work = 35×1 = 35. Time together = Work / Total Eff = 35 / (3+1) = 8.75 days. Tip: Efficiency is inversely proportional to Time.
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Question 63 of 100
A can do a piece of work in 12 days and B can do the same work in 15 days. Working together, in how many days will they finish the work?
ExplanationTotal work = LCM(12, 15) = 60 units. A's efficiency = 5 units/day, B's = 4. Combined efficiency = 9. Time = 60/9 = 6.67 days. Tip: LCM method avoids complex fraction additions.
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Question 64 of 100
A can do a piece of work in 30 days and B can do the same work in 20 days. Working together, in how many days will they finish the work?
ExplanationTotal work = LCM(30, 20) = 60 units. A's efficiency = 2 units/day, B's = 3. Combined efficiency = 5. Time = 60/5 = 12.0 days. Tip: LCM method avoids complex fraction additions.
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Question 65 of 100
A can do a work in 20 days, B in 30 days. A works for 2 days and leaves. In how many days can B finish the remaining work?
ExplanationTotal Work = LCM = 60. A's eff=3, B's eff=2. A's work in 2 days = 6. Remaining = 54. B takes 54/2 = 27.0 days. Tip: Calculate remaining work before changing dividing efficiency.
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Question 66 of 100
A can do a work in 15 days, B in 30 days. A works for 5 days and leaves. In how many days can B finish the remaining work?
ExplanationTotal Work = LCM = 30. A's eff=2, B's eff=1. A's work in 5 days = 10. Remaining = 20. B takes 20/1 = 20.0 days. Tip: Calculate remaining work before changing dividing efficiency.
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Question 67 of 100
Pipe A can fill a tank in 20 hours and Pipe B can fill it in 12 hours. How long will it take to fill the tank if both are opened together?
ExplanationLCM of 20, 12 is 60 (Total capacity). Eff A = 3, Eff B = 5. Time = 60 / (3 + 5) = 7.5 hours. Tip: Same logic as Time & Work.
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Question 68 of 100
A can do a work in 15 days, B in 20 days. A works for 5 days and leaves. In how many days can B finish the remaining work?
ExplanationTotal Work = LCM = 60. A's eff=4, B's eff=3. A's work in 5 days = 20. Remaining = 40. B takes 40/3 = 13.33 days. Tip: Calculate remaining work before changing dividing efficiency.
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Question 69 of 100
A can do a work in 20 days, B in 20 days. A works for 5 days and leaves. In how many days can B finish the remaining work?
ExplanationTotal Work = LCM = 20. A's eff=1, B's eff=1. A's work in 5 days = 5. Remaining = 15. B takes 15/1 = 15.0 days. Tip: Calculate remaining work before changing dividing efficiency.
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Question 70 of 100
A is 4 times as efficient as B. If B takes 32 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 32/4 = 8.0. Efficiencies: A=4, B=1. Total work = 32×1 = 32. Time together = Work / Total Eff = 32 / (4+1) = 6.4 days. Tip: Efficiency is inversely proportional to Time.
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Question 71 of 100
A is 2 times as efficient as B. If B takes 26 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 26/2 = 13.0. Efficiencies: A=2, B=1. Total work = 26×1 = 26. Time together = Work / Total Eff = 26 / (2+1) = 8.67 days. Tip: Efficiency is inversely proportional to Time.
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Question 72 of 100
A is 2 times as efficient as B. If B takes 23 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 23/2 = 11.5. Efficiencies: A=2, B=1. Total work = 23×1 = 23. Time together = Work / Total Eff = 23 / (2+1) = 7.67 days. Tip: Efficiency is inversely proportional to Time.
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Question 73 of 100
A can do a work in 25 days, B in 20 days. A works for 2 days and leaves. In how many days can B finish the remaining work?
ExplanationTotal Work = LCM = 100. A's eff=4, B's eff=5. A's work in 2 days = 8. Remaining = 92. B takes 92/5 = 18.4 days. Tip: Calculate remaining work before changing dividing efficiency.
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Question 74 of 100
A can do a work in 15 days, B in 30 days. A works for 2 days and leaves. In how many days can B finish the remaining work?
ExplanationTotal Work = LCM = 30. A's eff=2, B's eff=1. A's work in 2 days = 4. Remaining = 26. B takes 26/1 = 26.0 days. Tip: Calculate remaining work before changing dividing efficiency.
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Question 75 of 100
A can do a piece of work in 20 days and B can do the same work in 12 days. Working together, in how many days will they finish the work?
ExplanationTotal work = LCM(20, 12) = 60 units. A's efficiency = 3 units/day, B's = 5. Combined efficiency = 8. Time = 60/8 = 7.5 days. Tip: LCM method avoids complex fraction additions.
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Question 76 of 100
A can do a work in 25 days, B in 20 days. A works for 3 days and leaves. In how many days can B finish the remaining work?
ExplanationTotal Work = LCM = 100. A's eff=4, B's eff=5. A's work in 3 days = 12. Remaining = 88. B takes 88/5 = 17.6 days. Tip: Calculate remaining work before changing dividing efficiency.
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Question 77 of 100
A can do a work in 25 days, B in 30 days. A works for 3 days and leaves. In how many days can B finish the remaining work?
ExplanationTotal Work = LCM = 150. A's eff=6, B's eff=5. A's work in 3 days = 18. Remaining = 132. B takes 132/5 = 26.4 days. Tip: Calculate remaining work before changing dividing efficiency.
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Question 78 of 100
Pipe A can fill a tank in 5 hours while Pipe B can empty the full tank in 10 hours. If both are opened together, in how many hours will the tank be filled?
ExplanationCapacity = LCM(5,10) = 10. Net efficiency = Fill(2) - Empty(1) = 1. Time = 10 / 1 = 10.0 hours. Tip: Treat emptying pipes as negative efficiency.
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Question 79 of 100
A can do a piece of work in 30 days and B can do the same work in 10 days. Working together, in how many days will they finish the work?
ExplanationTotal work = LCM(30, 10) = 30 units. A's efficiency = 1 units/day, B's = 3. Combined efficiency = 4. Time = 30/4 = 7.5 days. Tip: LCM method avoids complex fraction additions.
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Question 80 of 100
A can do a piece of work in 12 days and B can do the same work in 10 days. Working together, in how many days will they finish the work?
ExplanationTotal work = LCM(12, 10) = 60 units. A's efficiency = 5 units/day, B's = 6. Combined efficiency = 11. Time = 60/11 = 5.45 days. Tip: LCM method avoids complex fraction additions.
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Question 81 of 100
A is 2 times as efficient as B. If B takes 37 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 37/2 = 18.5. Efficiencies: A=2, B=1. Total work = 37×1 = 37. Time together = Work / Total Eff = 37 / (2+1) = 12.33 days. Tip: Efficiency is inversely proportional to Time.
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Question 82 of 100
A is 4 times as efficient as B. If B takes 21 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 21/4 = 5.25. Efficiencies: A=4, B=1. Total work = 21×1 = 21. Time together = Work / Total Eff = 21 / (4+1) = 4.2 days. Tip: Efficiency is inversely proportional to Time.
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Question 83 of 100
Pipe A can fill a tank in 10 hours while Pipe B can empty the full tank in 15 hours. If both are opened together, in how many hours will the tank be filled?
ExplanationCapacity = LCM(10,15) = 30. Net efficiency = Fill(3) - Empty(2) = 1. Time = 30 / 1 = 30.0 hours. Tip: Treat emptying pipes as negative efficiency.
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Question 84 of 100
A can do a piece of work in 20 days and B can do the same work in 30 days. Working together, in how many days will they finish the work?
ExplanationTotal work = LCM(20, 30) = 60 units. A's efficiency = 3 units/day, B's = 2. Combined efficiency = 5. Time = 60/5 = 12.0 days. Tip: LCM method avoids complex fraction additions.
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Question 85 of 100
A can do a piece of work in 12 days and B can do the same work in 20 days. Working together, in how many days will they finish the work?
ExplanationTotal work = LCM(12, 20) = 60 units. A's efficiency = 5 units/day, B's = 3. Combined efficiency = 8. Time = 60/8 = 7.5 days. Tip: LCM method avoids complex fraction additions.
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Question 86 of 100
Pipe A can fill a tank in 20 hours and Pipe B can fill it in 20 hours. How long will it take to fill the tank if both are opened together?
ExplanationLCM of 20, 20 is 20 (Total capacity). Eff A = 1, Eff B = 1. Time = 20 / (1 + 1) = 10.0 hours. Tip: Same logic as Time & Work.
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Question 87 of 100
Pipe A can fill a tank in 15 hours while Pipe B can empty the full tank in 20 hours. If both are opened together, in how many hours will the tank be filled?
ExplanationCapacity = LCM(15,20) = 60. Net efficiency = Fill(4) - Empty(3) = 1. Time = 60 / 1 = 60.0 hours. Tip: Treat emptying pipes as negative efficiency.
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Question 88 of 100
A is 3 times as efficient as B. If B takes 37 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 37/3 = 12.33. Efficiencies: A=3, B=1. Total work = 37×1 = 37. Time together = Work / Total Eff = 37 / (3+1) = 9.25 days. Tip: Efficiency is inversely proportional to Time.
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Question 89 of 100
A is 4 times as efficient as B. If B takes 35 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 35/4 = 8.75. Efficiencies: A=4, B=1. Total work = 35×1 = 35. Time together = Work / Total Eff = 35 / (4+1) = 7.0 days. Tip: Efficiency is inversely proportional to Time.
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Question 90 of 100
A can do a work in 25 days, B in 20 days. A works for 5 days and leaves. In how many days can B finish the remaining work?
ExplanationTotal Work = LCM = 100. A's eff=4, B's eff=5. A's work in 5 days = 20. Remaining = 80. B takes 80/5 = 16.0 days. Tip: Calculate remaining work before changing dividing efficiency.
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Question 91 of 100
A is 3 times as efficient as B. If B takes 27 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 27/3 = 9.0. Efficiencies: A=3, B=1. Total work = 27×1 = 27. Time together = Work / Total Eff = 27 / (3+1) = 6.75 days. Tip: Efficiency is inversely proportional to Time.
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Question 92 of 100
A is 3 times as efficient as B. If B takes 26 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 26/3 = 8.67. Efficiencies: A=3, B=1. Total work = 26×1 = 26. Time together = Work / Total Eff = 26 / (3+1) = 6.5 days. Tip: Efficiency is inversely proportional to Time.
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Question 93 of 100
A is 3 times as efficient as B. If B takes 24 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 24/3 = 8.0. Efficiencies: A=3, B=1. Total work = 24×1 = 24. Time together = Work / Total Eff = 24 / (3+1) = 6.0 days. Tip: Efficiency is inversely proportional to Time.
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Question 94 of 100
A is 3 times as efficient as B. If B takes 29 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 29/3 = 9.67. Efficiencies: A=3, B=1. Total work = 29×1 = 29. Time together = Work / Total Eff = 29 / (3+1) = 7.25 days. Tip: Efficiency is inversely proportional to Time.
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Question 95 of 100
A is 2 times as efficient as B. If B takes 31 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 31/2 = 15.5. Efficiencies: A=2, B=1. Total work = 31×1 = 31. Time together = Work / Total Eff = 31 / (2+1) = 10.33 days. Tip: Efficiency is inversely proportional to Time.
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Question 96 of 100
A is 4 times as efficient as B. If B takes 37 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 37/4 = 9.25. Efficiencies: A=4, B=1. Total work = 37×1 = 37. Time together = Work / Total Eff = 37 / (4+1) = 7.4 days. Tip: Efficiency is inversely proportional to Time.
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Question 97 of 100
A is 3 times as efficient as B. If B takes 34 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 34/3 = 11.33. Efficiencies: A=3, B=1. Total work = 34×1 = 34. Time together = Work / Total Eff = 34 / (3+1) = 8.5 days. Tip: Efficiency is inversely proportional to Time.
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Question 98 of 100
A is 2 times as efficient as B. If B takes 28 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 28/2 = 14.0. Efficiencies: A=2, B=1. Total work = 28×1 = 28. Time together = Work / Total Eff = 28 / (2+1) = 9.33 days. Tip: Efficiency is inversely proportional to Time.
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Question 99 of 100
A is 2 times as efficient as B. If B takes 40 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 40/2 = 20.0. Efficiencies: A=2, B=1. Total work = 40×1 = 40. Time together = Work / Total Eff = 40 / (2+1) = 13.33 days. Tip: Efficiency is inversely proportional to Time.
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Question 100 of 100
A is 2 times as efficient as B. If B takes 32 days to complete a work alone, how many days will they take working together?
ExplanationA's days = 32/2 = 16.0. Efficiencies: A=2, B=1. Total work = 32×1 = 32. Time together = Work / Total Eff = 32 / (2+1) = 10.67 days. Tip: Efficiency is inversely proportional to Time.
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